p(X|A)*p(A)
p(A|X) = ---------------------------
p(X|A)*p(A) + p(X|~A)*p(~A) p(positive|cancer)*p(cancer)
-------------------------------------------------------------
p(positive|cancer)*p(cancer) + p(positive|~cancer)*p(~cancer)
which is
p(positive&cancer) / [p(positive&cancer) + p(positive&~cancer)]
which is
p(positive&cancer) / p(positive)
which is
p(cancer|positive)« Older Where did dynamic range go?... | Super Dollfies:... Newer »
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I got less than 3 hours of sleep last night and worked a 12+ hour day (damn you bored Korean crackers/open proxy maintainers).
What are the chances I can stay awake to read the rest of this very detailed article?
Go!
[Thanks Gyan!]
posted by togdon at 5:06 PM on July 21, 2004