# Line slope calculator 5x+2y=36

**Straight line given by points A[4; 8] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = -2.5x+18

**Canonical form of the line equation:**5x+2y-36 = 0

**Parametric form of the line equation:**

x = 2t+4

y = -5t+8 ; t ∈ R

**Slope:**m = -2.5

**Slope angle of line: φ =**-68°11'55″ = -1.1903 rad

**X intercept:**x

_{0}= 7.2

**Y intercept:**y

_{0}= q = 18

**Distance line from the origin:**d

_{0}= 6.685

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; -5)

**Normal vector: n =**(5; 2)

**Midpoint of the segment AB: M =**[5; 5.5]

**Perpendicular Bisector equation:**2x-5y+17.5 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 36°52'12″ = 0.6435 rad**